(C) Let the oxidation state of nitrogen be $x$.In $NH_2OH$,the oxidation states of $H$ is $+1$ and $O$ is $-2$.Applying the sum of oxidation states eq

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(C) Let the oxidation state of nitrogen be $x$.In $NH_2OH$,the oxidation states of $H$ is $+1$ and $O$ is $-2$.Applying the sum of oxidation states equal to zero:$x + 2(+1) + (-2) + 1 = 0$$x + 2 - 2 + 1 = 0$$x + 1 = 0$$x = -1$Thus,the oxidation state of nitrogen in $NH_2OH$ is $-1$.

Class 11 Chemistry Redox Reactions Oxidation number and Oxidation state

Medium

In which compound is the oxidation state of nitrogen $-1$?

A
$NO$
B
$N_2O$
C
$NH_2OH$
D
$N_2H_4$

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Redox Reactions

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Oxidation number and Oxidation state

Calculate the oxidation number of each sulfur atom in the following compounds:
$Na_2S_2O_3$
$Na_2S_4O_6$
$Na_2SO_3$
$Na_2SO_4$

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The oxidation state of elemental carbon is:

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Calculate the correct increasing order of average oxidation number of sulphur in $S_8, S_2O_3^{2-}, S_2O_7^{2-}, S_4O_6^{2-}, SO_3^{2-}$

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The oxidation number of carbon in $CH_2Cl_2$ is

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What are the oxidation numbers of hydrogen in $KH$,$MgH_2$,and $NaH$ respectively?

Medium

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In which compound is the oxidation state of nitrogen $-1$?

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Calculate the oxidation number of each sulfur atom in the following compounds:$Na_2S_2O_3$$Na_2S_4O_6$$Na_2SO_3$$Na_2SO_4$

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Calculate the oxidation number of each sulfur atom in the following compounds:
$Na_2S_2O_3$
$Na_2S_4O_6$
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